0=4[x-(2-x)]-7(x+1)

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Solution for 0=4[x-(2-x)]-7(x+1) equation:


Simplifying
0 = 4[x + -1(2 + -1x)] + -7(x + 1)
0 = 4[x + (2 * -1 + -1x * -1)] + -7(x + 1)
0 = 4[x + (-2 + 1x)] + -7(x + 1)

Reorder the terms:
0 = 4[-2 + x + 1x] + -7(x + 1)

Combine like terms: x + 1x = 2x
0 = 4[-2 + 2x] + -7(x + 1)
0 = [-2 * 4 + 2x * 4] + -7(x + 1)
0 = [-8 + 8x] + -7(x + 1)

Reorder the terms:
0 = -8 + 8x + -7(1 + x)
0 = -8 + 8x + (1 * -7 + x * -7)
0 = -8 + 8x + (-7 + -7x)

Reorder the terms:
0 = -8 + -7 + 8x + -7x

Combine like terms: -8 + -7 = -15
0 = -15 + 8x + -7x

Combine like terms: 8x + -7x = 1x
0 = -15 + 1x

Solving
0 = -15 + 1x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-1x' to each side of the equation.
0 + -1x = -15 + 1x + -1x
Remove the zero:
-1x = -15 + 1x + -1x

Combine like terms: 1x + -1x = 0
-1x = -15 + 0
-1x = -15

Divide each side by '-1'.
x = 15

Simplifying
x = 15

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